Case III: Unknown Mass- the Balance Principle:
Mass B: 267g
Mass D: 276g
Mass E: 218g
Mass F: 208g
Mass R: 147g
Percent Error:
((Actual-Expected)/Expected) *100
Mass B: 3.68%
Mass D: 1.8%
Mass E: 5.7%
Mass F: 5.7%
Mass R: 11.03%
Case lV: Meter Stick with One Mass:
x=.243m
m1=100g
m2=?
(.1)(.243)=(m2)(.257)
.946=m2
Approximate mass of meter stick: 94.6g
Actual Mass: 92.1g
Percent Error: (94.6-92.1)/94.6=2.64%
Lab Questions:
1. Torque depends on both the force and the length of the lever arm. A large force can produce little or no torque if the length of the moment arm is very small. A small force can produce a large torque if it is applied to a moment arm with a greater length.
2. The support force is not included in torque calculations because there is no net upward force on the meterstick. It is balanced, and therefore the downward force exerted on the support must be equal to the upward force exerted by it. If there is no net force, it will have no effect on the torque so it's left out of the calculations.
Case III: Unknown Mass- the Balance Principle:
Mass B: 267g
Mass D: 276g
Mass E: 218g
Mass F: 208g
Mass R: 147g
Percent Error:
((Actual-Expected)/Expected) *100
Mass B: 3.68%
Mass D: 1.8%
Mass E: 5.7%
Mass F: 5.7%
Mass R: 11.03%
Case lV: Meter Stick with One Mass:
x=.243m
m1=100g
m2=?
(.1)(.243)=(m2)(.257)
.946=m2
Approximate mass of meter stick: 94.6g
Actual Mass: 92.1g
Percent Error: (94.6-92.1)/94.6=2.64%
Lab Questions:
1. Torque depends on both the force and the length of the lever arm. A large force can produce little or no torque if the length of the moment arm is very small. A small force can produce a large torque if it is applied to a moment arm with a greater length.
2. The support force is not included in torque calculations because there is no net upward force on the meterstick. It is balanced, and therefore the downward force exerted on the support must be equal to the upward force exerted by it. If there is no net force, it will have no effect on the torque so it's left out of the calculations.
3. (220)(35)=(120)(50)+(m)(1)